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\problemgrouptitle{Solving Inequalities}

\begin{problemblock}{Solve the inequalities.}

\item $\displaystyle x^2-6x-7>0$
\answer{$(-\infty,-1)\cup(7,\infty)=\{x\in\mathset{R}\,|\, x<-1\ \mbox{or}\ x>7\}$}

\item $\displaystyle \frac{1-2x}{x^2+4x+3}\le 0$
\answer{$(-3,-1)\cup[1/2,\infty)=\{x\in\mathset{R}\,|\, -3<x<-1\ \mbox{or}\ x\ge1/2\}$}

\item $\displaystyle \frac{10}{7-x}<x$
\answer{$(2,5)\cup(7,\infty)=\{x\in\mathset{R}\,|\, 2<x<5\ \mbox{or}\ x>7\}$}

\end{problemblock}

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